Slope

Finding the slope:

Practice problem 1:

Find the slope of the line, which contains two points, is (34, 30) and (52,66 )

Answer: Slope of line = 2

Practice problem 2:

Find the slope of the line, which contains two points (11, 22) and (33, 88 )

Answer: Slope of line = 3

The above examples and practice problems are helpful to find the slope formula.

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Formula area

Equilateral triangle

Fraction simplification

How to simplify fractions?

A alloyed amount consists of an accumulation followed by a able fraction.

Example: The abnormal atom 8/5 can be afflicted to the alloyed amount 1 3/5 by adding the numerator (8) by the denominator (5). This gives a caliber of 1 and a butt of 3. The butt is placed over the divisor (5).

Question : Change the afterward abnormal fractions into alloyed Fractions:

a) 5/3 = 1 2/3

b) 11/2 = 5 1/2

c) 45/23 = 1 22/23

d) 13/5 = 2 3/5

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Online probability

Rectangle

Diagonal of a rectangle:

The Breadth of the rectangle blueprint is Breadth = breadth * width.

When barometer the breadth of any figure, the units for the breadth will be aboveboard units. In the blueprint for the breadth of a rectangle, breadth and amplitude are multiplied. If breadth and amplitude were both abstinent in yards, the artefact would be abstinent in yards squared.

The diagonals of a rectangle bifurcate anniversary added and are equal.

The Diagonal of a rectangle =

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Acute angles

Dividing square roots

2nd Shapes Names

2nd shapes names

In arithmetic, the geometric shapes are the shapes which are come in the topic geometry. In geometric shapes, the combinations of lines make each & every shape. There's different kind names of shapes in geometry. In this topic they are going to study about the names of shapes in geometry. .
Geometric Shapes are classified in to one classes :

* One dimensional (2-d) geometric shapes
* Two dimensional (3-d) geometric shapes

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Polygon cycles

Decimal to fraction chart

Linear Formula

Using the linear interpolation formula, find the equation for the given coordinates (6, 8) and (10, 16)

Sol:

Given coordinate values are (x₀, y₀) and (x₁, y₁) are (6, 8) and (10, 16).

y = y₀ + (x- x₀)

y = 8 + (x -6)

y = 8 + (x - 6) (8/4)

y = 8 + (x - 6)(2)

y = 8 + 2x - 12

y = 2x -12 + 8

y = 2x - 4

2x -y = 4 (or)

2x - y - 4 = 0.

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Diameter

Factors of 25